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12a^2-a-46=0
We add all the numbers together, and all the variables
12a^2-1a-46=0
a = 12; b = -1; c = -46;
Δ = b2-4ac
Δ = -12-4·12·(-46)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-47}{2*12}=\frac{-46}{24} =-1+11/12 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+47}{2*12}=\frac{48}{24} =2 $
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